7m^2-4m+8=8

Solution for 7m^2-4m+8=8 equation:

7m^2-4m+8=8

We move all terms to the left:

7m^2-4m+8-(8)=0

We add all the numbers together, and all the variables

7m^2-4m=0

a = 7; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·7·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*7}=\frac{0}{14}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*7}=\frac{8}{14}
=4/7
$